Question

Таня на 3 года младше своей сестры, а вместе им 27 лет. сколько лет каждой из них

Answer 1

х - лет Тане
(х+3) - лет Таниной сестре
1)х+ (Х+3) = 27
2х + 3 = 27
2х = 27 - 3
2х = 24
х=24 : 2
х = 12
12 лет Тане
2) 12+3 = 15 лет Таниной сестре
Ответ: 12 лет;  15 лет.

Answer 2

Таня- х 
сестра - х+3
всего- 27
 1)х+х+3 = 27
2х = 27- 3
2х = 24
х= 24:2
х=12
 12 лет тане
2) 12+3 = 15 лет сестре
ответ: 12 лет Тане, 15 лет сестре

Answer 3

Calculating the Ages of Tanya and Her Sister

To calculate the ages of Tanya and her sister, we can use the information provided that Tanya is 3 years younger than her sister and together they are 27 years old.

Let's denote Tanya's age as T and her sister's age as S.

We can create the following equations based on the given information: 1. T + S = 27 (together they are 27 years old) 2. S = T + 3 (Tanya is 3 years younger than her sister)

Solving the Equations

We can solve the system of equations to find the ages of Tanya and her sister.

Substituting the value of S from equation 2 into equation 1: T + (T + 3) = 27 2T + 3 = 27 2T = 27 - 3 2T = 24 T = 24 / 2 T = 12

Substituting the value of T back into equation 2 to find S: S = 12 + 3 S = 15

Conclusion

Based on the given information, Tanya is 12 years old and her sister is 15 years old.