Question

В цирке выступали обезьяны на двух-трехколесных велосипедах. Сколько было тех и других велосипедов, если всего было 8 велосипедов и 21 колесо?

Answer 1

допустим, у всех велосипедов по 2 колеса, тогда получим 8*2=16 колес

21-16=5колес осталось на трехколесные велосипеды ⇒ трехколесных велосипедов 5, тогда 8-5=3 двухколесных

Answer 2

Problem Analysis

We are given that monkeys performed in a circus on two or three-wheeled bicycles. We need to determine the number of each type of bicycle if there were a total of 8 bicycles and 21 wheels.

Solution

Let's assume that the number of two-wheeled bicycles is x and the number of three-wheeled bicycles is y.

We know that the total number of bicycles is 8, so we have the equation: x + y = 8 We also know that the total number of wheels is 21, which can be expressed as: 2x + 3y = 21 To solve this system of equations, we can use substitution or elimination. Let's use the elimination method.

Multiplying the first equation by 2, we get: 2x + 2y = 16 Subtracting this equation from the second equation, we can eliminate the x term: (2x + 3y) - (2x + 2y) = 21 - 16 y = 5 Substituting the value of y back into the first equation, we can solve for x: x + 5 = 8 x = 3 Therefore, there are 3 two-wheeled bicycles and 5 three-wheeled bicycles.

Answer

There were 3 two-wheeled bicycles and 5 three-wheeled bicycles in the circus.