Question

Из четырёх жертвователей второй дал вдвое больше первого, третий дал втрое больше второго , четвёртый вчетверо больше третьего, все вместе дали 132. сколько дал первый?РЕ ШЕНИЕ БЕЗ УРАВНЕНИЯ?

Answer 1

Это же Элементарно Ватсон! возьмем сумму первого заХ тогда

1- Х

2- 2Х

3- 6Х

4- 24Х

тогда  Х+2Х+6Х+24Х=132 отсюда Х=4 это и есть ответ=)

Answer 2

Problem Analysis

We are given that there are four donors, and the second donor gives twice as much as the first donor, the third donor gives three times as much as the second donor, and the fourth donor gives four times as much as the third donor. The total amount donated by all four donors is 132. We need to find out how much the first donor gave.

Solution

Let's assume that the amount donated by the first donor is x.

According to the given information: - The second donor gives twice as much as the first donor, so the second donor gives 2x. - The third donor gives three times as much as the second donor, so the third donor gives 3 * 2x = 6x. - The fourth donor gives four times as much as the third donor, so the fourth donor gives 4 * 6x = 24x.

The total amount donated by all four donors is 132, so we can write the equation: x + 2x + 6x + 24x = 132

Simplifying the equation: 33x = 132

Dividing both sides of the equation by 33: x = 4

Therefore, the first donor gave 4.

Answer

The first donor gave 4.