Question

Когда велосипедист проехал 2/3 пути, лопнула шина. На остальной путь пешком он затратил вдвое больше времени, чем на велосипедную езду. Во сколько раз велосипедист ехал быстрее,чем шёл?

Answer 1

 вроде бы в 2 раза он шол дольше 

Answer 2

Решение не могу сказать но предворительно я писала:
Так как он на остальной путь пешком он затратил вдвое больше времени, чем на велосипедную езду, а проехал он в два раза больше! (Чем прошел) То значит велосипед ехал в 4 раза больше чем он шел пешком! 
Незнаи мне дак 5 поставили:D

Answer 3

Problem Analysis

The problem states that a cyclist traveled 2/3 of the distance and then had a flat tire. The remaining distance was covered on foot, taking twice as long as the cycling portion. We need to determine how many times faster the cyclist was compared to walking.

Solution

Let's assume that the total distance is represented by D. The cyclist traveled 2/3 of the distance, which is equal to (2/3)D. The remaining distance covered on foot is (1/3)D.

According to the problem, the time taken to cover the remaining distance on foot is twice as long as the time taken to cycle the initial 2/3 of the distance.

Let's represent the time taken to cycle the initial 2/3 of the distance as T. Therefore, the time taken to cover the remaining distance on foot is 2T.

To find the ratio of the speed of cycling to walking, we can compare the distances covered in the same amount of time. Since the time taken to cover the remaining distance on foot is twice as long as the time taken to cycle the initial 2/3 of the distance, we can compare the distances covered in T time.

The distance covered in T time while cycling is (2/3)D, and the distance covered in T time while walking is (1/3)D.

To find the ratio of the speed of cycling to walking, we divide the distance covered while cycling by the distance covered while walking:

Ratio = (2/3)D / (1/3)D = 2/1 = 2

Therefore, the cyclist was 2 times faster than walking.

Answer

The cyclist was 2 times faster than walking.