Question

Приведите дробь: 1) 7/9 к знаменателю 27; 2)3/5 к 40 3)4/13 к 78 4)12/17 к 102 5)4/23 к 69 6)5/24 к 144

Answer 1

$\frac{7}{9} = \frac{7*3}{9*3}= \frac{21}{27} \\ \\ \frac{3}{5} =\frac{3*8}{5*8}=\frac{24}{40} \\ \\ \frac{4}{13}= \frac{4*6}{13*6}= \frac{24}{78} \\ \\ \frac{12}{17} =\frac{12*6}{17*6}= \frac{72}{702} \\ \\ \frac{4}{23} =\frac{4*3}{23*3} = \frac{12}{69} \\ \\ \frac{5}{24} =\frac{5*6}{24*6} = \frac{30}{144}$

Answer 2

1) 7/9 = (7/9) * (27/27) = 189/243 2) 3/5 = (3/5) * (8/8) = 24/40 3) 4/13 = (4/13) * (6/6) = 24/78 4) 12/17 = (12/17) * (6/6) = 72/102 5) 4/23 = (4/23) * (3/3) = 12/69 6) 5/24 = (5/24) * (6/6) = 30/144