Question

Хазяїн порахував що корова має вартість у 4 рази більше ніж собака, а кінь у 4 рази дорожче, ніж корова. Тому коли йшов з міста на ярмарок, захопив з собою 2000грн. На ці гроші він вкупив 1 собаку, 2 корови, і коня. Скільки кошьує кожна тварина?

Answer 1

собака пусть будет х

корова 4*х, а две коровы 2*4х=8х

лошадь будет 4*4х=16х

всего 2000

х+8х+16х=2000

25х=2000

х=2000:25

х=80 - стоит собака

80*4=320 стоит 1 корова

320*2=640 стоит 2 коровы

640*4=1280 стоит лошадь

Answer 2

Problem Analysis

The problem states that the owner calculated the value of a cow to be 4 times greater than that of a dog, and the value of a horse to be 4 times greater than that of a cow. The owner took 2000 UAH with him to the fair and bought 1 dog, 2 cows, and 1 horse. We need to determine the cost of each animal.

Solution

Let's assume the cost of a dog is x UAH. According to the problem, the cow's value is 4 times greater than that of a dog, so the cost of a cow would be 4x UAH. Similarly, the horse's value is 4 times greater than that of a cow, so the cost of a horse would be 16x UAH.

The owner spent 2000 UAH on the animals, so we can set up the following equation:

x + 2(4x) + 16x = 2000

Simplifying the equation:

x + 8x + 16x = 2000

25x = 2000

Solving for x:

x = 2000 / 25

x = 80

Therefore, the cost of a dog is 80 UAH, the cost of a cow is 4 * 80 = 320 UAH, and the cost of a horse is 16 * 80 = 1280 UAH.

Answer

The cost of each animal is as follows: - Dog: 80 UAH - Cow: 320 UAH - Horse: 1280 UAH