Question

Теплоход и катер отправились одновременно от одной пристани в одном и томже направлении. через 3ч катер обогнал теплоход на 75км. с какой средней скоростью двигался теплоход, если катер двигался со скоростью 45км/ч

Answer 1

45 х 3 = 135 км - прошел катер
135 - 75 = 60 км - прошел теплоход
60 : 3 = 20 км/час - скорость теплохода

Answer 2

75:3=25(км/ч)-на столько скоростькатера больше скорости теплохода.
45-25=20(км/ч) скорость теплохода.

Answer 3

Problem Setup

Two vessels, a boat and a cutter, departed from the same dock in the same direction at the same time. After 3 hours, the cutter overtook the boat by 75 km. The cutter was traveling at a speed of 45 km/h. We need to find the average speed of the boat.

Solution

Let's denote the speed of the boat as B and the time it took for the cutter to overtake the boat as t.

The distance covered by the boat in 3 hours is 3B, and the distance covered by the cutter in the same time is 3B + 75.

Using the formula: distance = speed × time, we can set up the equation: 3B + 75 = 45t

We also know that the distance covered by the boat in 3 hours is 3B, so: 3B = B × 3

Calculating the Boat's Speed

By substituting the value of 3B from the second equation into the first equation, we get: 3B + 75 = 45t 3B = B × 3

Solving for B: 3B + 75 = 45t 3B = 3B 0 = 45t - 3B - 75 3B = 45t - 75 B = (45t - 75) / 3

Substituting Known Values

We know that the cutter took 3 hours to overtake the boat, so t = 3. Substituting this value into the equation: B = (45*3 - 75) / 3 B = (135 - 75) / 3 B = 60 / 3 B = 20 km/h

So, the average speed of the boat was 20 km/h.