Question

Скорость лисы 18 м/с, а скорость зайца 15 м/с. лиса находится от зайца на расстояние 30 м. через сколько секунд, если ей повезёт, лиса догонит зайца?

Answer 1

18 - 15 = 3 ( м/с ) разница в скоростях
30 : 3 = 10 ( сек )
Ответ через 10 секунд

Answer 2

Problem Analysis

We are given that the speed of the fox is 18 m/s and the speed of the hare is 15 m/s. The fox is initially 30 m behind the hare. We need to determine how many seconds it will take for the fox to catch up to the hare.

Solution

To solve this problem, we can use the concept of relative speed. The relative speed is the difference between the speeds of the two objects. In this case, the relative speed of the fox with respect to the hare is 18 m/s - 15 m/s = 3 m/s.

Since the fox is initially 30 m behind the hare, it needs to cover this distance to catch up. The time it takes to cover a certain distance is given by the formula:

time = distance / speed

In this case, the distance is 30 m and the speed is the relative speed of 3 m/s. Substituting these values into the formula, we can calculate the time it will take for the fox to catch up to the hare.

Calculation

Using the formula time = distance / speed, we can calculate the time it will take for the fox to catch up to the hare:

time = 30 m / 3 m/s = 10 seconds

Therefore, if the fox is lucky, it will catch up to the hare in 10 seconds.

Answer

If the fox is lucky, it will catch up to the hare in 10 seconds.