Question

Внесите множитель под знак корня: а)3√11 б)-2√6 в)5а√а г)2х(х во 2 степени) √3х

Answer 1

А) √11*9=√99
б) √6*4=√24
в) √а*а*а*25= √25а³
г) √3х*4х²= √12х³

Answer 2

I can help you with your math question. To bring a multiplier under the root sign, you need to raise it to the power of the root index and multiply it by the expression under the root. For example, to bring 3 under the square root, you need to square it and get 9. Then you multiply 9 by the expression under the root. Here are the answers to your question:

a) $3\sqrt{11} = \sqrt{3^2 \cdot 11} = \sqrt{9 \cdot 11} = \sqrt{99}$

b) $-2\sqrt{6} = -\sqrt{2^2 \cdot 6} = -\sqrt{4 \cdot 6} = -\sqrt{24}$

c) $5a\sqrt{a} = \sqrt{5a^2 \cdot a} = \sqrt{5a^3}$

d) $2x(x^2)\sqrt{3x} = \sqrt{2x^3 \cdot 3x} = \sqrt{6x^4}$

I hope this helps you understand how to bring a multiplier under the root sign. If you want to learn more, you can check out this [website](https://math-prosto.ru/ru/pages/square_root/adding_under_the_root_sign/) that explains it in detail.