Question

Из центра круга площадь которого равна 400п см проведен перпендикуляр длиной 15 см к его плоскости найти расстояние от концов до точки аргумента

Answer 1

ΠR²=400πсм²
R²=400
R=20см
h=15см
l=√(R²+h²)=√(400+225)=√625=25см

Answer 2

Problem Analysis

We are given a circle with an area of 400 square centimeters. A perpendicular line of length 15 centimeters is drawn to its plane. We need to find the distance from the ends of the line to the point of argument.

Solution

To solve this problem, we can use the properties of a circle and the Pythagorean theorem.

Let's denote the radius of the circle as r. The area of the circle is given as 400 square centimeters, so we have the equation:

πr^2 = 400 Simplifying this equation, we can solve for r:

r^2 = 400/π

Taking the square root of both sides, we get:

r = √(400/π)

Now, let's consider the perpendicular line drawn to the plane of the circle. We can draw a right triangle with one leg as the radius of the circle (r) and the other leg as the length of the perpendicular line (15 cm). The hypotenuse of this triangle represents the distance from the ends of the line to the point of argument.

Using the Pythagorean theorem, we have:

r^2 + (15 cm)^2 = hypotenuse^2

Substituting the value of r from earlier, we get:

(400/π) + (15 cm)^2 = hypotenuse^2

Simplifying this equation, we can solve for the hypotenuse:

hypotenuse = √((400/π) + (15 cm)^2)

Calculating this value, we find that the distance from the ends of the line to the point of argument is approximately 18.77 cm.

Please note that the exact value of π has been approximated for simplicity.

Answer

The distance from the ends of the line to the point of argument is approximately 18.77 cm.