Question

1)7480-6480:120+80 2)1110+6890:13-130Помогите плиз

Answer 1

1)6480:120=54;7480-54=7426;7426+80=7506.
2)6890:13=530;1110+530=1640;1640-130=1510.

Answer 2

1) To solve the expression 7480-6480:120+80, we need to follow the order of operations, which is often remembered using the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

First, let's perform the division operation 6480:120, which gives us 54.

Next, we can substitute the result of the division back into the expression: 7480-54+80.

Now, we can perform the subtraction operation 7480-54, which gives us 7426.

Finally, we can perform the addition operation 7426+80, which gives us the final result of 7506.

2) To solve the expression 1110+6890:13-130, we again need to follow the order of operations.

First, let's perform the division operation 6890:13, which gives us approximately 529.23 (rounded to two decimal places).

Next, we can substitute the result of the division back into the expression: 1110+529.23-130.

Now, we can perform the addition operation 1110+529.23, which gives us approximately 1639.23 (rounded to two decimal places).

Finally, we can perform the subtraction operation 1639.23-130, which gives us the final result of 1509.23 (rounded to two decimal places).

I hope this helps! Let me know if you have any further questions.