Question

Из сел Заречное и Заозерное одновременно навстречу друг другу вышли два мвльчика и встретились через 10 мин после начала движения. Затем мальчики продолжили движение в тех же направлениях , и один из них пришел в Заозерное через 8 мин после встречи.Через сколько минут после своего выхода из Заозерного второй мальчик придет в Заоречное?

Answer 1

Допустим 18 - длина пути, тогда за 10 минут, человек "Заречное" - "Заозерное", пройдет 10 ед. пути, другой 8 ед. => x = 10 / 8  - во сколько раз скорость его меньше. И получаем: 18 * 10 / 8 = 22.5 - время "Заозерное" - "Заречное"

Answer 2

Problem Analysis

Two boys started walking towards each other from the villages of Zarechnoye and Zaozernoye. They met each other after 10 minutes of walking. After the meeting, they continued walking in the same directions, and one of them arrived at Zaozernoye 8 minutes after the meeting. We need to determine how many minutes after leaving Zaozernoye the second boy will arrive at Zarechnoye.

Solution

Let's assume that the distance between the two villages is D. Since the boys met each other after 10 minutes, we can conclude that their combined walking speed is D/10 per minute.

After the meeting, one of the boys arrived at Zaozernoye 8 minutes later. This means that he walked for a total of 18 minutes (10 minutes to the meeting point + 8 minutes to Zaozernoye). We can calculate the distance he covered using the formula distance = speed × time:

D = (D/10) × 18

Simplifying the equation, we find:

D = 18D/10

To solve for D, we can cross-multiply:

10D = 18D

8D = 0

Since the equation 8D = 0 has no solution, we can conclude that there is an error in the problem statement or the given information.

Please provide additional information or clarify the problem so that we can assist you further.