Question

Задача из двух городов вышли одновремено навстречу друг другупоезда и встретились через 18 часов определи скорость каждого поезда если растояние мнжду городами 1620 км а скорость одного поезда на 10 км больше чем скорость другого

Answer 1

Пусть скорость 1 x км/ч, тогда 2 (x+10).Прошло 18 ч.Всего 1620 км. Составим уравнение:
1.)(x+x+10)×18=1620
2x+10=1620÷18
2x+10=90
2x=90-10
2x=80
x=80÷2
x=40км/ч-скорость первого поезда.
2.)40+10=50км/ч-скорость второго поезда.

Answer 2

Problem Analysis

To solve this problem, we need to determine the speed of each train given the distance between the cities, the time it took for them to meet, and the fact that one train is traveling 10 km/h faster than the other.

Solution

Let's assume the speed of the slower train is x km/h. According to the problem, the speed of the faster train is x + 10 km/h.

We know that the time it took for the trains to meet is 18 hours, and the distance between the cities is 1620 km.

To find the speeds of the trains, we can use the formula: speed = distance / time.

Let's calculate the speeds of the trains:

The speed of the slower train is x km/h, and the speed of the faster train is x + 10 km/h.

The time it took for the trains to meet is 18 hours.

The distance between the cities is 1620 km.

Using the formula speed = distance / time, we can set up the following equations:

For the slower train: x = 1620 / 18.

For the faster train: x + 10 = 1620 / 18.

Now, let's solve these equations to find the speeds of the trains.

Calculation

For the slower train: x = 1620 / 18 = 90 km/h.

For the faster train: x + 10 = 1620 / 18 = 90 + 10 = 100 km/h.

Answer

Therefore, the speed of the slower train is 90 km/h, and the speed of the faster train is 100 km/h.

Please let me know if there's anything else I can help you with!