Question

Группа туристов 1 ч ехала на автобусе,а затем шла 6ч пешком со скоростью,на 18 км\ч меньшей чем скорость автобуса.Всего группа преодолела 67 км.Найдите скорость автобуса и туристовв пешем походе.

Answer 1

Пусть х скорость автобуса, то скорость пешком х-18 отсюда:
х+(х-18)*6=67
х+6х-108=67
7х=175
х=25 км/час скорость автобуса
25-18=7 км/час скорость туристов в пешем походе

Answer 2

Problem Analysis

The group of tourists traveled for 1 hour by bus and then walked for 6 hours at a speed 18 km/h slower than the bus. The total distance covered was 67 km. We need to find the speed of the bus and the speed of the tourists during the hike.

Solution

Let's denote the speed of the bus as x km/h and the speed of the tourists during the hike as x - 18 km/h.

The total distance covered by the bus is given by the formula: distance = speed × time.

The total distance covered by the tourists during the hike is given by the formula: distance = speed × time.

We can use these formulas to create an equation and solve for the speeds.

Calculation

The total distance covered by the bus and the tourists during the hike can be expressed as: 1. 1 hour × x km/h (bus speed) 2. 6 hours × (x - 18) km/h (tourists' speed during the hike)

According to the problem, the total distance covered is 67 km. Therefore, we can write the equation: 1 hour × x km/h + 6 hours × (x - 18) km/h = 67 km.

Solving this equation will give us the speed of the bus and the speed of the tourists during the hike.

Equation

The equation to solve is: x + 6x - 108 = 67.

Solution

Solving the equation: 7x - 108 = 67, 7x = 175, x = 25.

Answer

The speed of the bus is 25 km/h and the speed of the tourists during the hike is 7 km/h.