Question

в коробке лежат 4 цвет. каранд. и 10 простых. какое наименьшее кол-во каранд. нужно взять из коробки не глядя чтобы оказалось 2 цветн. и 3 простых карандаша?

Answer 1

всего 10 простых их придется вынимать, плюс два нужных цветных.

значит вытаскиваем 12 карандашей среди них будет не менее 2 цветных и 3 простых

Answer 2

Calculating the Minimum Number of Colored and Plain Pencils Needed

To find the minimum number of colored and plain pencils needed from the box, we can use a system of equations to represent the given information. Let's denote the number of colored pencils as c and the number of plain pencils as p.

We are given the following information: 1. There are 4 colored pencils and 10 plain pencils in the box. 2. We need to take some pencils from the box without looking and ensure that we have 2 colored pencils and 3 plain pencils.

We can represent this information with the following system of equations: - c + p = total pencils - c = 4 - p = 10 - c - 2 = 2 - p - 3 = 10

Solving these equations will give us the minimum number of colored and plain pencils needed.

Solution

Using the given information and the system of equations, we can solve for the minimum number of colored and plain pencils needed.

From the first equation, we know that c + p = total pencils. Substituting the given values, we have: - 4 + 10 = total pencils - 14 = total pencils

So, the total number of pencils in the box is 14.

Next, we need to find the minimum number of colored pencils needed. From the second equation, we know that c = 4, so we need 4 colored pencils.

Similarly, we need to find the minimum number of plain pencils needed. From the third equation, we know that p = 10, so we need 10 plain pencils.

Therefore, the minimum number of colored pencils needed is 4 and the minimum number of plain pencils needed is 10.

Final Answer

To ensure that we have 2 colored pencils and 3 plain pencils, we need to take 4 colored pencils and 10 plain pencils from the box without looking.