Question

Помогите, пожалуйста) У трьох пакетах було порівну горіхів. Коли з кожного пакета взяли по 6 горіхів, то в них стало стільки горіхів, скільки було раніше в двох пакетах. Скільки горіхів було в кожному пакеті спочатку?

Answer 1

Коли з кожного пакета взяли по 6 горіхів, то залишилося тільки 2 пакети горіхів.
Значить забрали сумарно вміст одного пакета горіхів.
6*3=18 - горіхів було в кожному пакеті спочатку

Answer 2

Problem Analysis

We are given that there were an equal number of nuts in three packages. When 6 nuts were taken from each package, the number of nuts remaining in the packages was equal to the number of nuts that were originally in two of the packages. We need to determine the initial number of nuts in each package.

Solution

Let's assume that there were x nuts in each package initially.

According to the problem, when 6 nuts were taken from each package, the number of nuts remaining in the packages was equal to the number of nuts that were originally in two of the packages.

So, after taking 6 nuts from each package, there were x - 6 nuts remaining in each package.

And the total number of nuts remaining in the three packages is 3 * (x - 6).

This total number of nuts remaining is equal to the number of nuts that were originally in two of the packages, which is 2x.

Therefore, we can set up the equation:

3 * (x - 6) = 2x

Now, let's solve this equation to find the value of x.

Expanding the equation:

3x - 18 = 2x

Subtracting 2x from both sides:

x - 18 = 0

Adding 18 to both sides:

x = 18

Therefore, there were initially 18 nuts in each package.

Answer

There were initially 18 nuts in each package.