Question

0.6(4х-3)+2.1(х-5)= 2.5(4а-8b)-(3a-4b)*1.4= -(-5.2-3.1t)-(2.4t-6.4)=

Answer 1

1) 0,6(4x-3)+2,1(x-5)=0.
2,4x-1,8+2,1x-10,5
2,4x+2,1x=1,8+10,5
4,5x=12,3
2) 2,5(4a-8b)-(3a-4b)×1,4=0
10a-20b-4,2a+5,6b
10a-4,2a=20b-5,6b
5,8a=14,4b
3) -(-5,2-3,1t)-(2,4t-6,4)=0
5,2+3,1t+2,4t+6,4
3,1t+2,4t=-5,2-6,4
5,5t=-11,6

Answer 2

0.6(4х-3)+2.1(х-5)=2,4х-1,8+2,1х-10,5= 4,5х-12,3
2.5(4а-8b)-(3a-4b)*1.4=10а-20b-4,2a+5,6b=5,8а-14,4
-(-5.2-3.1t)-(2.4t-6.4)=5,2+3,1t-2,4t+6,4= 0,7t+11,6

Answer 3

I can help you with your math problem. Here is the detailed solution:

$$0.6(4x-3)+2.1(x-5)=2.5(4a-8b)-(3a-4b)\cdot 1.4=-(-5.2-3.1t)-(2.4t-6.4)$$

First, we simplify the left side by distributing the coefficients and combining like terms:

$$2.4x-1.8+2.1x-10.5=2.5(4a-8b)-(3a-4b)\cdot 1.4=-(-5.2-3.1t)-(2.4t-6.4)$$

$$4.5x-12.3=2.5(4a-8b)-(3a-4b)\cdot 1.4=-(-5.2-3.1t)-(2.4t-6.4)$$

Next, we simplify the right side by distributing the coefficients and combining like terms:

$$4.5x-12.3=10a-20b-4.2a+5.6b=-(-5.2-3.1t)-(2.4t-6.4)$$

$$4.5x-12.3=5.8a-14.4b=5.2+3.1t+2.4t-6.4$$

Then, we move all the variables to one side and all the constants to the other side by adding or subtracting both sides:

$$4.5x-5.8a+14.4b-5.2-3.1t-2.4t=-12.3-6.4$$

$$4.5x-5.8a+14.4b-5.5t=-18.7$$

Finally, we divide both sides by the coefficient of x to isolate x:

$$x=\frac{-18.7}{4.5}+\frac{5.8a}{4.5}-\frac{14.4b}{4.5}+\frac{5.5t}{4.5}$$

$$x=-4.16+1.29a-3.2b+1.22t$$

This is the final answer. You can check it by plugging it back into the original equation and verifying that both sides are equal. I hope this helps you. Have a nice day.Ответь+подробно.+0.6(4х-3)+2.1(х-5)=+2.5(4а-8b)-(3a-4b)*1.4=+-(-5.2-3.1t)-(2.4t-6.4)=