Question

два поезда вышли из двух городов одновременно навстречу друг другу.Один поезд шёл со скоростью 63 км/час.С какой скоростью шёл второй поезд,если расстояние между городами 564км?Встретились поезда через 4 часа.

Answer 1

1) 63*4=252 км проехал второй поезд
2) 564-252=312 км проехал первый поезд
3) 312:4=78 км/ч скорость поезда

Answer 2

564 = 4 * ( 63 + Х ) 
63 + Х = 141 
X = 141 - 63
X = 78 ( км\час ) 
Ответ 78 км\час 

Answer 3

Problem Analysis

We are given that two trains start from two cities simultaneously and travel towards each other. The first train has a speed of 63 km/h. We need to find the speed of the second train if the distance between the cities is 564 km and the trains meet after 4 hours.

Calculation

To solve this problem, we can use the formula: distance = speed × time.

Let's assume the speed of the second train is x km/h.

The first train travels for 4 hours at a speed of 63 km/h, so the distance it covers is: distance = speed × time = 63 km/h × 4 h = 252 km.

The second train also travels for 4 hours at a speed of x km/h, so the distance it covers is: distance = speed × time = x km/h × 4 h = 4x km.

Since the total distance between the cities is 564 km, we can write the equation: 252 km + 4x km = 564 km.

Now, let's solve this equation to find the value of x.

Solution

To find the speed of the second train, we need to solve the equation 252 km + 4x km = 564 km.

Subtracting 252 km from both sides of the equation, we get: 4x km = 564 km - 252 km.

Simplifying the right side of the equation, we have: 4x km = 312 km.

Dividing both sides of the equation by 4, we get: x km = 312 km / 4.

Calculating the value, we find: x = 78 km/h.

Therefore, the second train was traveling at a speed of 78 km/h.

Answer

The second train was traveling at a speed of 78 km/h.