Question

Два поезда вышли навстречу друг другу одновременно из двух городов, расстояние между которыми 495 км. Через 3 ч они встретились. Какова скорость каждого поезда, если известно, что скорость одного из них на 5 км/ч больше скорости другого?

Answer 1

1й поезд: 80км/ч
2й поезд: 85км/ч удачи тебе

Answer 2

Х-скорость 1-го поезда
х+5-скорость 2-го поезда
1) (х+(х+5))×3=495
(2х+5)×3=495
2х+5=495:3
2х+5=165
2х=165-5
2х=160
х=160:2
х=80км/ч-скорость 1-го поезда
2)80+5=85км/ч-скорость 2-го поезда.

Answer 3

Problem Analysis

We have two trains that start from two different cities and travel towards each other. The distance between the cities is 495 km. After 3 hours, the trains meet each other. We need to find the speed of each train, given that the speed of one train is 5 km/h greater than the speed of the other train.

Solution

Let's assume the speed of the slower train is x km/h. Then, the speed of the faster train would be x + 5 km/h.

To find the speed of each train, we can use the formula:

Speed = Distance / Time

The distance traveled by the slower train in 3 hours would be 3x km, and the distance traveled by the faster train in 3 hours would be 3(x + 5) km.

Since the total distance between the cities is 495 km, we can set up the equation:

3x + 3(x + 5) = 495

Simplifying the equation:

3x + 3x + 15 = 495

6x + 15 = 495

6x = 480

x = 80

Therefore, the speed of the slower train is 80 km/h, and the speed of the faster train is 80 + 5 = 85 km/h.

Answer

The speed of the slower train is 80 km/h, and the speed of the faster train is 85 km/h.