Question

Ластівка за 4 год польоту подолала 276км. 5 - 6 цього шляху чиж пролетів за 5 год. На скільки швидкість ластівки була більшою за швидкість чижа

Answer 1

$v=s/t$$v_{lastivka} =276/4=69$км/год
з чижом так само підставляємо в рівняння і порівнюємо

Answer 2

(276/4)-(276/6*5)/5=23 км

Answer 3

Calculation of Speed

To determine the speed of the swallow and the finch, we can use the formula:

Speed = Distance / Time

Given that the swallow flew a distance of 276 km in 4 hours, we can calculate its speed as follows:

Swallow's Speed = 276 km / 4 hours = 69 km/h [[1]]

To find out if the finch flew faster than the swallow, we need to calculate the distance it covered. We know that the finch flew for 5 hours and covered 5/6 of the total distance. Let's calculate the distance covered by the finch:

Distance covered by the finch = (5/6) * 276 km = 230 km

Now, we can calculate the speed of the finch using the formula mentioned earlier:

Finch's Speed = 230 km / 5 hours = 46 km/h [[1]]

Comparison of Speeds

Comparing the speeds of the swallow and the finch, we can see that the swallow's speed was greater than the finch's speed.

The swallow's speed (69 km/h) was greater than the finch's speed (46 km/h).

Please note that these calculations are based on the given information and assumptions made.