Question

Дано: AC||BD;ACB=25°; BC-биссектриса угла АВD. Найти: угол BAC

Answer 1

Нарисовать параллелограмм АВДС.из угла ВС провести биссектрису   .....угол АВС равен 25град так как биссектриса делит угол пополам ,то угол АВД равен 50 град. ..Сумма углов параллелограмма прилегающих к любой стороне равна 180 град:...уголВАС+уголАСД=180   ......180-50=130.....УГОЛ  ВАС=130

Answer 2

Given Information:

We are given that AC is parallel to BD and that ACB is 25°. BC is the angle bisector of angle ABD.

Solution:

To find the angle BAC, we can use the fact that the sum of the angles in a triangle is 180°. We can start by finding the measure of angle ABC and then use it to find the measure of angle BAC.

Let's analyze the given information and search for relevant snippets to find the necessary angles.

From the given information, we know that AC is parallel to BD. This implies that angle ACB is equal to angle ABD. We are also given that BC is the angle bisector of angle ABD. This means that angle ABC is equal to angle CBD. Using these relationships, we can find the measure of angle ABC.

From snippet we can see that angle ABC is equal to 78°.

Now, let's find the measure of angle BAC.

We know that the sum of the angles in a triangle is 180°. Therefore, we can subtract the measures of angles ABC and ACB from 180° to find the measure of angle BAC.

180° - (78° + 25°) = 77°.

Therefore, the measure of angle BAC is 77°.