Question

Один вертоліт пролетів 480 км,а другий 800км.Перший вертоліт був у польоті на 2 години менше.Скільки годинбув у польоті кожний вертоліт,якщоїх швидкістьоднакова?

Answer 1

1)800-480=320(км)-менше пролетів перший вертоліт ніж другий;
2)320÷2=160(км)-пролітав кожен з них за годину;
3)480÷160=3(год.)-був у польоті перший вертоліт;
4)800÷160=5(год.)-був у польоті другий вертоліт

Answer 2

Problem Analysis

We are given that two helicopters flew different distances, with one helicopter flying 480 km and the other flying 800 km. The first helicopter was in flight for 2 hours less than the second helicopter. We need to determine how many hours each helicopter was in flight, assuming their speeds were the same.

Solution

Let's assume the speed of both helicopters is v km/h.

We can use the formula distance = speed × time to find the time each helicopter was in flight.

For the first helicopter, the distance is 480 km and the time is t hours. Therefore, we have the equation:

480 = v × t ---(1)

For the second helicopter, the distance is 800 km and the time is t + 2 hours. Therefore, we have the equation:

800 = v × (t + 2) ---(2)

To solve this system of equations, we can substitute the value of t from equation (1) into equation (2) and solve for v.

Let's solve the equations step by step:

From equation (1), we can express t in terms of v:

t = 480 / v ---(3)

Substituting equation (3) into equation (2), we get:

800 = v × (480 / v + 2)

Simplifying the equation:

800 = 480 + 2v

Rearranging the equation:

2v = 800 - 480

2v = 320

v = 320 / 2

v = 160

Now that we have the value of v, we can substitute it back into equation (1) to find the value of t:

480 = 160 × t

Simplifying the equation:

t = 480 / 160

t = 3

Therefore, the first helicopter was in flight for 3 hours and the second helicopter was in flight for 3 + 2 = 5 hours.

Answer

If the speed of both helicopters is the same, the first helicopter was in flight for 3 hours and the second helicopter was in flight for 5 hours.