Question

два мальчика идут навстречу друг другу.сейчас между ними 12км.скорость одного из них составляет ноль целый две третьих скорости другого.найдите скорость движения каждого мальчика.если известно что они встретятся через 1.5ч есечто веленкин номер1199

Answer 1

х скорость первого мальчика

2х/3 скорость воторого

1,5х - прошел до встречи первый; 1,5*2х/3=х прошел до встречи второй

вместе они прошли 12км:

1,5х+х=12

2,5х=12

х=4,8 км/ч скорость первого

2*4,8/3=3,2 км/ч скорость второго

 

Answer 2

х+2/3х =12 : 1,5

5/3х= 8

х= 4,8 км/ч скорость 1 мальчика

4,8 : 3 * 2 = 3,2 км/ч скорость 2 мальчика

Answer 3

Problem Analysis

Two boys are walking towards each other, and the distance between them is 12 km. The speed of one of the boys is zero and the speed of the other boy is two-thirds the speed of the first boy. They will meet after 1.5 hours. We need to find the speed of each boy.

Solution

Let's assume the speed of the first boy is x km/h. Since the speed of the second boy is two-thirds of the first boy's speed, the speed of the second boy is (2/3)x km/h.

We can use the formula distance = speed × time to find the distance traveled by each boy. Since they are walking towards each other, the sum of their distances will be equal to the total distance between them, which is 12 km.

The distance traveled by the first boy is x × 1.5 km, and the distance traveled by the second boy is (2/3)x × 1.5 km. The sum of these distances should be equal to 12 km.

So, we can set up the equation:

x × 1.5 + (2/3)x × 1.5 = 12

Now, let's solve this equation to find the value of x.

Calculation

x × 1.5 + (2/3)x × 1.5 = 12

Multiplying both sides by 2 to eliminate the fraction:

2 × (x × 1.5) + 2 × ((2/3)x × 1.5) = 2 × 12

3x + 2x = 24

5x = 24

x = 24 / 5

x = 4.8

The speed of the first boy is 4.8 km/h.

The speed of the second boy is (2/3) × 4.8 = 3.2 km/h.

Therefore, the speed of the first boy is 4.8 km/h and the speed of the second boy is 3.2 km/h.

Answer

The speed of the first boy is 4.8 km/h and the speed of the second boy is 3.2 km/h.

Note: The provided information about "Velenkin number 1199" is not relevant to the question and will not be addressed.