Question

Сравни выражения, не вычисляя их значений а) - 0,01*(1.415)и 27 1/3*(-7.28) б)-30,2*2,51 и 30,2*(-2,51) в)96,48*(- 8 5/12) и 0,0038*0,014 г)(-12,4)квадрате и (-

Answer 1

А) - 0,01*(1.415)> 27 1/3*(-7.28) б)-30,2*2,51 = 30,2*(-2,51) в)96,48*(- 8 5/12) < 0,0038*0,014 отрицательное число меньше положительного; из двух отрицательных чисел больше то, модуль которого меньше; 

Answer 2

To compare the expressions without calculating their values, let's analyze each expression separately:

a) -0.01 * (1.415) and 27 + 1/3 * (-7.28):

-0.01 * (1.415) can be simplified by multiplying -0.01 by 1.415, resulting in -0.01415.

27 + 1/3 * (-7.28) can be simplified by multiplying 1/3 by -7.28, resulting in -2.42667. Then, adding 27 to -2.42667 gives us 24.57333.

Comparing the two simplified expressions, we have: -0.01415 compared to 24.57333.

b) -30.2 * 2.51 and 30.2 * (-2.51):

-30.2 * 2.51 can be simplified by multiplying -30.2 by 2.51, resulting in -75.802.

30.2 * (-2.51) can be simplified by multiplying 30.2 by -2.51, resulting in -75.802.

Comparing the two simplified expressions, we have: -75.802 compared to -75.802.

c) 96.48 * (-8 + 5/12) and 0.0038 * 0.014:

To simplify 96.48 * (-8 + 5/12), we first need to simplify the expression inside the brackets.

-8 + 5/12 can be converted to a common denominator: -8 * 12/12 + 5/12, resulting in (-96 + 5)/12 = -91/12.

Now, we can multiply 96.48 by -91/12, resulting in -702.36.

To simplify 0.0038 * 0.014, we multiply the two numbers directly, resulting in 0.0000532.

Comparing the two simplified expressions, we have: -702.36 compared to 0.0000532.

d) (-12.4) squared and (-5) squared:

To square a number, we multiply it by itself.

(-12.4) squared can be calculated by multiplying -12.4 by -12.4, resulting in 153.76.

(-5) squared can be calculated by multiplying -5 by -5, resulting in 25.

Comparing the two squared expressions, we have: 153.76 compared to 25.

Please note that the comparison is done without calculating the actual values of the expressions, but rather by analyzing the simplified forms of the expressions.