
Если шахматист А. играет белыми фигурами, то он выигрывает у шахматиста Б. с вероятностью 0,5. Если
А. играет чёрными, то А. выигрывает у Б. с вероятностью 0,32. Шахматисты А. и Б. играют две партии, причём во второй партии меняют цвет фигур. Найдите вероятность того, что А. выиграет ровно один раз.

Ответы на вопрос

Выиграл в первой игре - р1 = 0,5
Вероятность проиграть в первой игре - q1 = 1 - p1 = 0.5.
ИЛИ - в первой проиграл, но выиграл во второй - Р =q1*p2 = 0.5*0.32 = 0.16.
Вероятности событий - ИЛИ - суммируются - 0,5+ 0,32 = 0,82 = 82%-ОТВЕТ



Calculation of the Probability
To find the probability that player A wins exactly one game out of the two games they play, we need to consider two scenarios:
1. Player A wins the first game and loses the second game. 2. Player A loses the first game and wins the second game.
Let's calculate the probability for each scenario separately and then add them together.
Scenario 1: Player A wins the first game and loses the second game
The probability that player A wins the first game while playing as white is 0.5 The probability that player A loses the second game while playing as black is 0.68 (1 - 0.32).
To calculate the probability of both events happening, we multiply the probabilities together:
Probability of Scenario 1 = Probability of A winning as white * Probability of A losing as black = 0.5 * 0.68 = 0.34
Scenario 2: Player A loses the first game and wins the second game
The probability that player A loses the first game while playing as white is 0.5 The probability that player A wins the second game while playing as black is 0.32.
To calculate the probability of both events happening, we multiply the probabilities together:
Probability of Scenario 2 = Probability of A losing as white * Probability of A winning as black = 0.5 * 0.32 = 0.16
Total Probability
To find the total probability that player A wins exactly one game, we add the probabilities of the two scenarios together:
Total Probability = Probability of Scenario 1 + Probability of Scenario 2 = 0.34 + 0.16 = 0.5
Therefore, the probability that player A wins exactly one game out of the two games they play is 0.5.
Please note that the probabilities used in this calculation are taken from the search result snippets


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