Question

Помогите пожалуйста. школьный спортивный зал имеет следующие размеры его ширина в 3 раза меньше длины а высота совпадает с шириной найдите объем параллелепипеда соответствующего спортивному залу если сумма всех упомянутых измерений составляет 35 м

Answer 1

Пусть а ширина, б длина, с высота.
a=b/3
c=a=b/3
b/3+b+b/3=35
b+2b/3=35
3b/3+2b3=35
5b/3=35
5b=35*3
5b=105
b=105/5
b=21 (м) длина
а=21/3=7 (м) ширина
с=а=7 (м) высота
a+b+c=35
21+7+7=35
V=21*7*7=1029 (м3)

Answer 2

Calculation of the Volume of the School Sports Hall

To find the volume of the parallelepiped corresponding to the school sports hall, we need to determine the dimensions of the parallelepiped based on the given information.

Let's denote the length of the sports hall as L, the width as W, and the height as H.

According to the given information: - The width of the sports hall is 3 times smaller than the length: W = (1/3)L. - The height of the sports hall is the same as the width: H = W.

We also know that the sum of all the mentioned dimensions is 35 meters: L + W + H = 35.

To find the values of L, W, and H, we can solve this system of equations.

Substituting the value of W in terms of L into the equation L + W + H = 35, we get:

L + (1/3)L + (1/3)L = 35

Simplifying the equation, we have:

(7/3)L = 35

Dividing both sides of the equation by (7/3), we find:

L = 15

Substituting this value of L back into the equation W = (1/3)L, we get:

W = (1/3)(15) = 5

Since H = W, we have:

H = 5

Therefore, the dimensions of the parallelepiped corresponding to the school sports hall are: - Length: L = 15 meters - Width: W = 5 meters - Height: H = 5 meters

To calculate the volume of the parallelepiped, we multiply the length, width, and height:

Volume = L * W * H = 15 * 5 * 5 = 375 cubic meters

Therefore, the volume of the parallelepiped corresponding to the school sports hall is 375 cubic meters.

Please note that the sources provided do not contain relevant information for this specific calculation.