
Автобус выехал в Углич в 8 часов утра и ехал четыре часа со скоростью 60 км/ч. за это время было
пройдено три четвертых всего расстояния. с какой скоростью автобус проехал оставшуюся часть пути, если в Углич экскурсанты пробыли ровно в час того же дня ?

Ответы на вопрос

2)240 км это 3/4 пути, значит 240/3=80 км. Это одна треть пути
3)80*4=320 км это весь путь
4) час дня-это 13 часов, значит 13-8=5 часов всего в пути
5)5-4=1 час осталось проехать автобусу
6)80*1=80км/ч ехал автобус оставшуюся часть пути



Problem Analysis
We are given that a bus left Uglich at 8:00 AM and traveled for four hours at a speed of 60 km/h. During this time, the bus covered three-fourths of the total distance. We need to determine the speed at which the bus traveled the remaining distance, given that the tourists stayed in Uglich for exactly one hour on the same day.Solution
Let's assume the total distance traveled by the bus is D km.According to the given information, the bus traveled for four hours at a speed of 60 km/h. Therefore, the distance covered in four hours is:
Distance covered in four hours = Speed x Time = 60 km/h x 4 h = 240 km.
We are also given that during this time, the bus covered three-fourths of the total distance. Therefore, we can write the equation:
240 km = (3/4)D.
To find the remaining distance, we need to subtract the distance covered in four hours from the total distance:
Remaining distance = Total distance - Distance covered in four hours = D - 240 km.
We are also given that the tourists stayed in Uglich for exactly one hour on the same day. Therefore, the total time taken by the bus is five hours:
Total time = Time traveled for four hours + One hour stay in Uglich = 4 hours + 1 hour = 5 hours.
To find the speed at which the bus traveled the remaining distance, we can use the formula:
Speed = Distance / Time.
Substituting the values, we have:
Speed = (D - 240 km) / 5 hours.
Now, we can solve this equation to find the speed at which the bus traveled the remaining distance.
Calculation
Let's solve the equation to find the speed at which the bus traveled the remaining distance.240 km = (3/4)D
Multiplying both sides by 4/3:
320 km = D
Substituting this value into the equation for speed:
Speed = (D - 240 km) / 5 hours
Speed = (320 km - 240 km) / 5 hours
Speed = 80 km / 5 hours
Speed = 16 km/h
Answer
The bus traveled the remaining distance at a speed of 16 km/h.Explanation
The total distance traveled by the bus is 320 km. The bus traveled for four hours at a speed of 60 km/h, covering a distance of 240 km. The remaining distance is 320 km - 240 km = 80 km. The bus took a total of five hours for the journey, including a one-hour stay in Uglich. Therefore, the speed at which the bus traveled the remaining distance is 80 km / 5 hours = 16 km/h.


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