Question

Решить задачу: В компьютерном тире давали вначале возможность сделать 5 выстрелов в мишень. При каждом попадании в мишень можно было сделать ещё 3 выстрела дополнительно. Приз получал тот, кто смог сделать не менее 25 выстрелов. Петя получил приз. Какое минимальное количество раз он мог попасть в мишень?

Answer 1

4 выстрела из 5
потомучто он попадает и ему дают 3 выстрела дополнительно.
(4+3)=7
7*4=28 выстрелов получилось у Пети

Answer 2

8*3=24
9*3=27
получается 9 раз он попал

Answer 3

Problem Analysis

In this problem, we are given that in a computer shooting game, the player is initially given 5 shots at a target. Each time the player hits the target, they are allowed to take an additional 3 shots. The player must make a minimum of 25 shots to win a prize. We need to determine the minimum number of times that Petya could have hit the target to win the prize.

Solution

To solve this problem, we can work backwards from the minimum number of shots required to win the prize (25) and determine the minimum number of times Petya could have hit the target.

Let's analyze the possible scenarios:

1. If Petya hit the target exactly 25 times, it means she made 5 shots initially and then hit the target 20 more times after each successful shot. This scenario is valid.

2. If Petya hit the target 26 times, it means she made 5 shots initially, hit the target 3 times after the first successful shot, and then hit the target 18 more times after each successful shot. This scenario is also valid.

3. If Petya hit the target 27 times, it means she made 5 shots initially, hit the target 3 times after the first successful shot, hit the target 3 times after the second successful shot, and then hit the target 15 more times after each successful shot. This scenario is also valid.

We can continue this pattern until we reach a scenario where Petya hit the target 25 times. Therefore, the minimum number of times Petya could have hit the target is 25.

Answer

The minimum number of times Petya could have hit the target to win the prize is 25.

Note: The sources provided do not contain any relevant information for solving this problem.