Question

Реши задачу:Задача 67:В рассказе А. П. Чехова "Репетитор" гимназист Егор Зиберов не сумел решить арифметическую задачу, а отец репетируемого ученика, отставной губернский секретарь Удодов, пощелкав на счетах, получил правильный ответ. Решите и Вы эту задачу арифметически? Вот она. Купец купил 138 аршин черного и синего сукна за 540 руб. Спрашивается, сколько аршин купил он и того и другого, если синее стоило 5 руб. за аршин, а черное - 3 руб.? (запишите два числа цифрами через пробел без запятых).

Answer 1

1) 540:5=18 (р)- синего
2)138:3=46 (р)-черного
18 46

Answer 2

Arithmetic Problem from A.P. Chekhov's "Tutor"

Sure, let's solve the arithmetic problem from A.P. Chekhov's "Tutor."

The problem states that a merchant bought 138 arshins of black and blue cloth for 540 rubles. The blue cloth cost 5 rubles per arshin, and the black cloth cost 3 rubles per arshin. We need to find out how many arshins of each type the merchant bought.

To solve this problem, we can use a system of linear equations.

Let's denote: - x as the number of arshins of blue cloth - y as the number of arshins of black cloth

We can then form the following equations based on the given information: 1. x + y = 138 (equation representing the total number of arshins) 2. 5x + 3y = 540 (equation representing the total cost in rubles)

Now, let's solve this system of equations to find the values of x and y.

First, we can solve equation 1 for x: x = 138 - y

Then, we substitute this value of x into equation 2: 5(138 - y) + 3y = 540

Solving for y: 690 - 5y + 3y = 540 690 - 2y = 540 -2y = 540 - 690 -2y = -150 y = -150 / -2 y = 75

Now that we have the value of y, we can find the value of x: x = 138 - 75 x = 63

So, the merchant bought 63 arshins of blue cloth and 75 arshins of black cloth.

Therefore, the answer to the problem is: 63 75