Question

В дом мельницы привезли 58 мешков пшеницы и 38 мешков ячменя, пшеницы привезли на 16 центнеров больше, чем ячменя, сколько отдельно килограммов ячменя и пшеницы завезено, если все мешки с зерном имели одинаковую массу

Answer 1

1) 58-38=20м - больше с пшеницей

2) 1600/20=80кг в одном мешке

3)58*80=4640кг-пшеницы

4)38*80=3040кг-ячменя 

Answer 2

1)58-38=на 20мешков больше-привезли пшеницы.

16ц=1600кг.

2)1600:20=80кг-в одном мешке.

3)58*80=4640кг-привезли пшеницы.

4)38*80=3040кг-привезли ячменя.

Answer 3

Problem Analysis

We are given that 58 sacks of wheat and 38 sacks of barley were delivered to a mill. The wheat delivery was 16 centners (1 centner = 100 kilograms) more than the barley delivery. We need to find the separate weights of wheat and barley in kilograms, assuming that all sacks had the same weight.

Solution

Let's assume that the weight of each sack of wheat is x kilograms. Therefore, the weight of each sack of barley would be x - 16 kilograms.

To find the total weight of wheat, we multiply the number of sacks (58) by the weight of each sack (x). Similarly, to find the total weight of barley, we multiply the number of sacks (38) by the weight of each sack (x - 16).

We can set up the following equation:

58x + 38(x - 16) = total weight of wheat + total weight of barley

Simplifying the equation:

58x + 38x - 608 = total weight of wheat + total weight of barley

96x - 608 = total weight of wheat + total weight of barley

Since the total weight of wheat and barley is the same as the total weight of all the sacks, we can rewrite the equation as:

96x - 608 = (58 + 38)x

Simplifying further:

96x - 608 = 96x

We can see that the variable x cancels out, which means that the equation has no solution. This implies that there is no unique weight for each sack of wheat and barley that satisfies the given conditions.

Therefore, we cannot determine the separate weights of wheat and barley based on the information provided.

Conclusion

Based on the given information, we cannot determine the separate weights of wheat and barley that were delivered to the mill. The equation derived from the information does not have a unique solution.