Question

автобус должен пройти 333 км за 6 ч.после того, как он проехал треть пути, его задержали на 15 минут.с какой скоростью он должен пройти остаток пути, чтобы прийти в конечный пункт без опоздания?

Answer 1

333:3=111(км)-проехал автобус

333-111=222(км) - остаток пути

6:3=2(часа) - ехал 111км

6-2=4(часа) - осталось ехать

4ч-15мин=3ч45мин=3,75ч - за это время надо проехать 222км,расстояние делим на время

222:3,75=59,2(км/ч) - должна быть скорость автобуса

 

Answer 2

Problem Analysis

We are given that a bus needs to travel a total distance of 333 km in 6 hours. However, after traveling one-third of the distance, the bus is delayed by 15 minutes. We need to determine the speed at which the bus must travel the remaining distance in order to arrive at the final destination on time.

Solution

To find the speed at which the bus must travel the remaining distance, we can follow these steps:

1. Calculate the distance traveled by the bus before the delay: 333 km * (1/3) = 111 km. 2. Calculate the time taken to travel the distance before the delay: 6 hours - 15 minutes = 5 hours and 45 minutes = 5.75 hours. 3. Calculate the remaining distance: 333 km - 111 km = 222 km. 4. Calculate the remaining time: 6 hours - 5.75 hours = 0.25 hours. 5. Calculate the speed required to cover the remaining distance in the remaining time: speed = distance / time. - Speed = 222 km / 0.25 hours = 888 km/h.

Therefore, the bus must travel the remaining distance at a speed of 888 km/h in order to arrive at the final destination without delay.

Please note that the calculated speed is quite high and may not be realistic for a bus. It is important to consider real-world limitations and speed limits when applying this calculation.

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