
Две группы зрителей за одинаковые по цене билеты в цирк заплатили 1800 руб. и 3050 руб. Сколько
стоил один билет, если в одной группе было на 5 человек больше, чем в другой?Закончи схематический чертеж к задаче и реши её.

Ответы на вопрос

1250 : 5 = 250 руб -стоимость одного билета






Problem Analysis
We are given that two groups of spectators paid a total of 1800 rubles and 3050 rubles for tickets to a circus. One group had 5 more people than the other. We need to find the cost of one ticket.Let's assume that the smaller group had x people, so the larger group had x + 5 people. We can set up the following equation based on the given information:
x * ticket_cost + (x + 5) * ticket_cost = 1800 + 3050
Simplifying the equation, we get:
2x * ticket_cost + 5 * ticket_cost = 4850
Solution
To find the cost of one ticket, we need to solve the equation:2x * ticket_cost + 5 * ticket_cost = 4850
Let's solve this equation to find the value of ticket_cost.
2x * ticket_cost + 5 * ticket_cost = 4850
Factoring out the ticket_cost:
(2x + 5) * ticket_cost = 4850
Dividing both sides by (2x + 5):
ticket_cost = 4850 / (2x + 5)
Now, we need to find the value of x to calculate the ticket cost. Unfortunately, the problem does not provide any additional information to determine the value of x. Therefore, we cannot solve the problem without this information.
Schematic Diagram
Unfortunately, the problem does not provide any specific information to create a schematic diagram. However, we can represent the problem using a simple equation:x * ticket_cost + (x + 5) * ticket_cost = 1800 + 3050
Conclusion
In conclusion, we cannot determine the cost of one ticket without additional information about the value of x, which represents the number of people in the smaller group.

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