Question

Одна улитка в 8 часов утра начала взбираться на дерево со скоростью 2м.час В 10 часов утра вторая улитка начала двигаться по дереву из той же точки в том же направлении и догнала первую через 4 часа С какой скоростью двигалась вторая улитка?

Answer 1

1) 8*2=16 (м) - прошла первая улитка, когда вышла вторая
2) 8*4=32 (м) - еще прошла первая улитка прежде чем ее догнала вторая
3) 32+16=48 (м) - общий пройденный путь двумя улитками
4) 48:4=12 (м/ч) - скорость второй улитки

Answer 2

Problem Analysis

We are given that one snail starts climbing a tree at a speed of 2 m/h at 8 am. Another snail starts moving along the tree from the same point and in the same direction at 10 am. The second snail catches up with the first snail after 4 hours. We need to determine the speed of the second snail.

Solution

Let's assume the speed of the second snail is x m/h.

The first snail climbs for a total of 4 hours before being caught by the second snail. Therefore, the distance covered by the first snail is:

Distance = Speed × Time = 2 m/h × 4 h = 8 m

The second snail catches up with the first snail after 4 hours. During this time, the second snail covers the same distance as the first snail, which is 8 meters. Therefore, we can set up the following equation:

Distance = Speed × Time = 8 m = x m/h × 4 h

Simplifying the equation, we find:

x = 8 m / 4 h = 2 m/h

Therefore, the speed of the second snail is 2 m/h.

Answer

The second snail moved at a speed of 2 m/h.