Question

Одно число на 17 больше другого при делении больщого числа на меньшее неполное частное оавно 1 найдите остаток

Answer 1

Делимое а, делитель b, неполное частное с, остаток r, тогда a=b*c+r.
У нас: меньшее число х (делитель) , большее х+17 (делимое) , неполное частное 1, остаток r.
x+17=x*1+r
x+17=x+r
r=17
Ответ: остаток 17.

Answer 2

Problem Analysis

We are given that one number is 17 greater than another number. When the larger number is divided by the smaller number, the resulting quotient is 1. We need to find the remainder.

Solution

Let's assume the smaller number is x and the larger number is x + 17.

According to the given information, when the larger number is divided by the smaller number, the quotient is 1. Mathematically, we can represent this as:

x + 17 = x * 1 + remainder

Simplifying the equation, we have:

x + 17 = x + remainder

Since the quotient is 1, the remainder must be 0. Therefore, the equation becomes:

x + 17 = x + 0

Simplifying further, we get:

17 = 0

This equation is not possible to solve because it is contradictory. There is no value of x that satisfies this equation.

Therefore, there is no solution to this problem.

Conclusion

The given problem does not have a solution. The equation 17 = 0 is contradictory and cannot be satisfied by any value of x.