Question

В розыгрыше первенства участвуют 12 команд. Команды, занявшие первые три места, награждаются золотой, серебряной и бронзовой медалями, а две последние команды покидают первенство.сколько различных результатов первенства существует?

Answer 1

Все подробно расписал. Ответ: 4 результата.

Answer 2

Number of Possible Results in the Championship

To determine the number of different results in the championship, we need to consider the placement of the 12 participating teams. The teams that finish in the top three positions will receive gold, silver, and bronze medals, while the two bottom teams will be eliminated from the championship.

To calculate the number of different results, we can use the concept of permutations, specifically the permutation of 12 teams taken 3 at a time for the top three positions. The remaining 7 teams will automatically be assigned the remaining positions.

The formula for calculating permutations is:

P(n, r) = n! / (n - r)!

Where: - n is the total number of items (12 teams in this case) - r is the number of items taken at a time (3 teams in this case) - ! denotes the factorial of a number (the product of all positive integers less than or equal to the number)

Using this formula, we can calculate the number of different results in the championship:

P(12, 3) = 12! / (12 - 3)! = 12! / 9! = (12 * 11 * 10) / (3 * 2 * 1) = 220

Therefore, there are 220 different results possible in the championship.