Question

Помогите решить задачу:В двух карманах было 28 орехов,причём в левом кармане в 3 раза больше,чем в правом.Сколько было орехов в каждом кармане?НУЖНО СОСТАВИТЬ УРАВНЕНИЕ!

Answer 1

Обозначим 1 карман как х, тогда второй 3х, известно, что всего было 28:
х+3х=28
4х=28
х=28:4
х=7 (1 карман)
7*3=21 (2 карман)

Answer 2

Пусть в левом кармане было-3х орехов, тогда в правом-х. Составим уравнение:
х+3х=28
4х=28
х=7 орехов-в правом кармане
7*3=21 орех-в левом кармане

Answer 3

Problem Analysis

We are given that there are a total of 28 nuts in two pockets, with the left pocket having three times as many nuts as the right pocket. We need to determine the number of nuts in each pocket.

Formulating the Equation

Let's assume that the number of nuts in the right pocket is x. According to the problem, the number of nuts in the left pocket is three times the number of nuts in the right pocket, which can be represented as 3x. The sum of the nuts in both pockets is 28, so we can write the equation:

x + 3x = 28

Simplifying the equation:

4x = 28

Solving the Equation

To solve for x, we divide both sides of the equation by 4:

x = 28 / 4

Simplifying further:

x = 7

Finding the Number of Nuts in Each Pocket

Now that we have found the value of x, we can substitute it back into the equation to find the number of nuts in each pocket.

Number of nuts in the right pocket (x): 7 Number of nuts in the left pocket (3x): 3 * 7 = 21

Therefore, there are 7 nuts in the right pocket and 21 nuts in the left pocket.

Answer

There are 7 nuts in the right pocket and 21 nuts in the left pocket.