Question

Решения задач с помощью уравнения Отец в 8 раз старше дочери а дочь на 28 лед моложе отца. сколько лет отцу 2) мать в 6 раз старше сына а сын на 25 лет моложе матери сколько лет матири????

Answer 1

1) Х-возраст дочери
  составляем уравнение: Х * 8=Х+28
 8 Х - Х = 28
 7 Х=28
Х= 28:7
 Х= 4 года (возраст дочери)
возраст отца (8 Х): 4 * 8 = 32 года 
2) Х - возраст сына
Х * 6 = Х + 25
 6 Х - Х = 25
 5 Х = 25  
Х = 25:5
  Х = 5 лет (возраст сына)
возраст матери (6 Х) 6 * 5 = 30 лет 

Answer 2

Problem 1: Father and Daughter's Ages

The problem states that the father is 8 times older than the daughter, and the daughter is 28 years younger than the father. We need to find the age of the father.

Let's assume the daughter's age is represented by D and the father's age is represented by F.

According to the problem, we have two equations:

1. The father is 8 times older than the daughter: F = 8D. 2. The daughter is 28 years younger than the father: D = F - 28.

To find the age of the father, we can substitute the value of D from equation 2 into equation 1:

F = 8(F - 28).

Now, let's solve this equation to find the age of the father.

Solution to Problem 1:

To find the age of the father, we can solve the equation F = 8(F - 28).

Expanding the equation, we get:

F = 8F - 224.

Simplifying further, we have:

7F = 224.

Dividing both sides of the equation by 7, we find:

F = 32.

Therefore, the age of the father is 32 years.