Question

У хозяйки 3 корзины с яблоками.Всего 60 кг яблок .В первой и второй вместе 38 кг ,а во второйи третьей вместе 40 кг. Сколько кг яблок в кождой.

Answer 1

1)60-38 равно 22 кг - в третьей корзине
2) 60-40 равно 20 кг- в первой корзине
3)60-(22+20) равно 18 кг- во второй корзине
ответ; в 1-ой 20 кг,во 2-ой 18 кг, в 3-ей 22 кг

Answer 2

Х первая корзина
У вторая
Z третья

Х+у+z=60
X+y=38
Y+z=40

X+y=60-z
60-z=38
Z=60-38
Z=22

Y+22=40
Y=40-22
Y=18

X+18=38
X=20

Answer 3

Solution:

To solve this problem, we can use a system of linear equations to find the weight of apples in each basket.

Let's denote the weight of apples in the first, second, and third baskets as x, y, and z respectively.

We have the following information: 1. x + y = 38 (weight of apples in the first and second baskets together) 2. y + z = 40 (weight of apples in the second and third baskets together) 3. x + y + z = 60 (total weight of apples)

We can solve these equations to find the values of x, y, and z.

Calculation:

From equation 1, we can express x in terms of y: x = 38 - y Substitute this value of x into equation 3: (38 - y) + y + z = 60 38 + z = 60 z = 60 - 38 z = 22 Now, substitute the value of z into equation 2: y + 22 = 40 y = 40 - 22 y = 18 Finally, substitute the value of y into equation 1: x + 18 = 38 x = 38 - 18 x = 20

Answer:

So, the weight of apples in each basket is: - First basket (x): 20 kg - Second basket (y): 18 kg - Third basket (z): 22 kg