
ВЕЛОСЕПЕДИСТ ДВИГАЕТСЯ СО СКОРОСТЬ 20КМ\Ч ПРОЕХАЛ ПУТЬ МЕЖДУ ДВУМЯ ГОРОДАМИ ЗА 3 ЧАСА ВОЗВРОЩАЯСЬ
ОН ПРОЕХАЛ ТОТЖЕ ПУТЬ ЗА 4 ЧАСА С КАКОЙ СКОРОСТЬЮ ВЕЛОСЕПЕДИСТ ПРОЕДИТ ОБРАТНЫЙ ПУТЬ

Ответы на вопрос

2)60км/4ч=15км/ч-скорость
ОТВЕТ.15КМ/Ч -СКОРОСТЬ ВЕЛОСИПЕДИСТА НА ОБРАТНОМ ПУТИ



Calculation of Speed and Distance
To calculate the speed at which the cyclist traveled on the return journey, we can use the formula:
Speed = Distance / Time
Let's denote the speed of the cyclist on the forward journey as S1 and the speed on the return journey as S2. The time taken for the forward journey is given as 3 hours, and the time taken for the return journey is given as 4 hours.
From the information provided, we know that the cyclist traveled the same distance on both the forward and return journeys. Therefore, we can set up the following equation:
Distance / S1 = 3 (Equation 1)
Distance / S2 = 4 (Equation 2)
To find the speed of the cyclist on the return journey, we need to solve these two equations simultaneously.
Solving the Equations
Let's solve the equations using substitution:
From Equation 1, we can express the distance in terms of S1:
Distance = S1 * 3
Substituting this into Equation 2, we get:
S1 * 3 / S2 = 4
Now, we can solve for S2:
S2 = (S1 * 3) / 4
Calculation of Speed on the Return Journey
To find the speed at which the cyclist traveled on the return journey, we need to know the speed on the forward journey. The information provided states that the cyclist traveled at a speed of 20 km/h on the forward journey.
Substituting S1 = 20 km/h into the equation for S2, we get:
S2 = (20 * 3) / 4 = 15 km/h
Therefore, the cyclist traveled at a speed of 15 km/h on the return journey.
Conclusion
The cyclist traveled at a speed of 20 km/h on the forward journey and at a speed of 15 km/h on the return journey.
Note: The sources provided do not contain specific information related to this calculation. The calculation is based on the given information and the application of mathematical principles.


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