Question

X^2-4x+5=0. (Квадратное уравнение) Решите пожалуйста

Answer 1

X^2 - 4x + 5 = 0
найдем дискриминант уравнения D  .    D = (-4)^2 - 4 * 1 *5 = 16 - 20 = - 4
Дискриминант уравнения меньше 0  , значит  действительных корней нет

Answer 2

Solving the Quadratic Equation x^2 - 4x + 5 = 0

To solve the quadratic equation x^2 - 4x + 5 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 1, b = -4, and c = 5. Substituting these values into the quadratic formula, we get:

x = (-(-4) ± √((-4)^2 - 4(1)(5))) / (2(1))

Simplifying further:

x = (4 ± √(16 - 20)) / 2

x = (4 ± √(-4)) / 2

Since the discriminant (b^2 - 4ac) is negative, the equation has no real solutions. The solutions are complex numbers.

Therefore, the quadratic equation x^2 - 4x + 5 = 0 has no real solutions.