Question

Через две трубы бассейн наполняется за 6 ч, через первую трубу - за 15 ч. За сколько времени можно наполнить бассейн через вторую трубу? заранеее спс!

Answer 1

Задача: За сколько времени можно наполнить бассейн через вторую трубу?
Ответ: За 2,5ч можно наполнить бассейн через вторую трубку ;3

Answer 2

Problem Analysis

We are given that a pool can be filled in 6 hours using two pipes, and one of the pipes can fill the pool in 15 hours. We need to determine how long it would take to fill the pool using the second pipe.

Solution

Let's assume that the first pipe can fill the pool in x hours. According to the given information, the pool can be filled in 6 hours using both pipes and in 15 hours using the first pipe alone.

To find the rate at which each pipe fills the pool, we can use the formula:

Rate = Work / Time

Let's calculate the rates for both pipes:

- Rate of filling the pool using both pipes: 1 pool / 6 hours = 1/6 pool per hour - Rate of filling the pool using the first pipe alone: 1 pool / 15 hours = 1/15 pool per hour

Since the rates are additive, we can subtract the rate of the first pipe from the rate of both pipes to find the rate of the second pipe:

Rate of the second pipe = Rate of both pipes - Rate of the first pipe

Rate of the second pipe = (1/6 - 1/15) pool per hour

Simplifying the expression:

Rate of the second pipe = (5/30 - 2/30) pool per hour

Rate of the second pipe = 3/30 pool per hour

Simplifying further:

Rate of the second pipe = 1/10 pool per hour

Therefore, the second pipe can fill 1/10 of the pool in 1 hour.

To find the time it would take to fill the pool using the second pipe alone, we can use the formula:

Time = Work / Rate

Since we want to fill the entire pool, the work is 1 pool. Substituting the values:

Time = 1 pool / (1/10 pool per hour)

Simplifying the expression:

Time = 1 pool * (10/1) hours

Time = 10 hours

Therefore, it would take 10 hours to fill the pool using the second pipe alone.

Answer

It would take 10 hours to fill the pool using the second pipe alone.