Question

AO=AB, OB=12 см, Poab=58 см, AO=?​

Answer 1

Ответ:

Ответ:

АС=12см

ОС=9см

Объяснение:

АС=12см =АВ

ОС радиус, и ∆АОС прямоугольный, тогда 15²=12²+ОС²

225-144=ОС²

ОС=9 см

Пошаговое объяснение:

Надеюсь сделаешь лучшим ответом⛓️

Answer 2

I will answer your question in detail. AO=AB, OB=12 cm, Poab=58 cm, AO=?

The question is about finding the length of the segment AO, given that it is equal to the segment AB, and that the perimeter of the triangle OAB is 58 cm. We also know that the length of the segment OB is 12 cm.

To solve this problem, we can use the formula for the perimeter of a triangle, which is the sum of the lengths of its sides. In this case, we have:

Poab = AO + AB + OB

Since AO = AB, we can simplify this as:

Poab = 2 * AO + OB

Substituting the given values, we get:

58 = 2 * AO + 12

Solving for AO, we get:

AO = (58 - 12) / 2

AO = 23

Therefore, the length of the segment AO is 23 cm.