Question

В двух карзинах было 20 груш.Когда из первой карзины взяли 4 груши;в обеих карзинах стало поровну.Сколько было груш в каждой карзине сначала.(решение и условие пожалуйста)

Answer 1

Если прибавили 4 ко 2 корзине 20-4=16(если поровну) 16-4=12(изночально было)Ответ в 1 корзине было 20, а в 2 корзине 12 . Вот и все чего тут сложного?

Answer 2

Problem Statement:

В двух корзинах было 20 груш. Когда из первой корзины взяли 4 груши, в обеих корзинах стало поровну. Сколько было груш в каждой корзине сначала?

Solution:

Let's assume that the number of pears in the first basket is x, and the number of pears in the second basket is y.

According to the problem statement, there were initially 20 pears in total. So we can write the equation:

x + y = 20 After taking 4 pears from the first basket, the number of pears in both baskets became equal. This means that the number of pears in the second basket is equal to the number of pears remaining in the first basket after taking 4 pears.

So we can write the equation:

x - 4 = y Now we have a system of two equations with two variables. We can solve this system to find the values of x and y.

Solving the system of equations:

From equation we can rewrite it as:

x = y + 4

Substituting this value of x into equation we get:

y + 4 + y = 20

Simplifying the equation:

2y + 4 = 20

Subtracting 4 from both sides:

2y = 16

Dividing both sides by 2:

y = 8

Substituting this value of y back into equation we get:

x - 4 = 8

Adding 4 to both sides:

x = 12

Therefore, there were initially 12 pears in the first basket and 8 pears in the second basket.

So, the answer is: - The first basket initially had 12 pears. - The second basket initially had 8 pears.