Question

У трьох цистернах було 10720л пального. У першій і третій цистернах разом було 7870л у другій і третій 6020л. Ск літрів пального було в третій цистерні?

Answer 1

1 ц-? л
2 ц-?л
3 ц-?л
1+3=7870л (стрелочек нет, надеюсь поймете как это записать в условии)
2+3=6020л
1+2+3=10720л
10720-7870=2850 (л) во второй ц.
10720-6020=4700 (л) в первой ц.
2850+4700=7550 (л) в первой и второй ц.
10720-7550=3170 (л)в третьей.

Answer 2

I can understand and communicate fluently in Ukrainian. Your question is about solving a system of linear equations. Let x, y, and z be the amount of fuel in the first, second, and third tanks, respectively. Then, we have the following equations:

$$ \\begin{cases} x + y + z = 10720 \\\\ x + z = 7870 \\\\ y + z = 6020 \\end{cases} $$

To solve this system, we can use the elimination method. First, we subtract the second equation from the first equation to get:

$$ y = 10720 - 7870 = 2850 $$

Then, we substitute this value of y into the third equation to get:

$$ z = 6020 - 2850 = 3170 $$

Finally, we substitute this value of z into the second equation to get:

$$ x = 7870 - 3170 = 4700 $$

Therefore, the amount of fuel in the third tank is 3170 liters. You can learn more about solving systems of linear equations from [this tutorial](https://www.w3schools.com/python/python_user_input.asp).