Question

На двух базах было 45т арбузов. Когда с первой базы вывезли 8т200кг арбузов, а со второй в 4 раза больше , то на второй базе арбузов не осталось.Сколько арбузов осталось на первой базе и сколько их было на второй базе ? заранее спасибо

Answer 1

1)45т=45000кг
2)45000-8200=36800(кг) осталось на 1 базе
3)3600*4=147200(кг) их было на 2 базе

Answer 2

8т200*4=32т800кг арбузов вывезли со второй базы                                                1тонна=1000кг                                                                                                            45000-(8200+32800)=45000-41000=4000кг арбузов осталось на 1 базе                4000+8200=12200кг(12т200кг арбузов было на 1 базе)                                           32800кг или 32 т 800 кг арбузов было на 2 базе                                         

Answer 3

Problem Analysis

To solve this problem, we need to determine the number of watermelons left on the first base and the initial quantity on the second base. We know that there were 45,000 watermelons in total, 8,200 were taken from the first base, and four times that amount were taken from the second base. Additionally, there were no watermelons left on the second base after the removal.

Calculation

Let's denote: - x as the number of watermelons left on the first base - y as the initial number of watermelons on the second base

We can create the following equations based on the given information: 1. x + 4 * 8200 = y (the total number of watermelons taken from the second base is 4 times the amount taken from the first base) 2. x + y = 45000 (the total number of watermelons on both bases)

Solution

We can solve the system of equations to find the values of x and y.

First, we can use the second equation to express y in terms of x: y = 45000 - x

Substitute this expression for y into the first equation: x + 4 * 8200 = 45000 - x

Solving for x: 5x = 45000 - 4 * 8200 5x = 45000 - 32800 5x = 12200 x = 12200 / 5 x = 2440

Now that we have the value of x, we can find y: y = 45000 - x y = 45000 - 2440 y = 42560

Answer

The number of watermelons left on the first base is 2440, and the initial number of watermelons on the second base was 42560.