Question

1. Выбрать точку, принадлежащею графику функции y=3-x 2. Найти ноль функции y=-3x+15Срочно хелп​

Answer 1

Пошаговое объяснение:

1

У=3-х

Х=0

У=3

А(0;3)

2

У= - 3Х+15

-3Х+15=0

-3Х= - 15

Х=5 ноль функции

Answer 2

1. To find a point on the graph of the function y = 3 - x^2, we need to substitute a value for x and calculate the corresponding value of y. Let's choose x = 0:

When x = 0, y = 3 - (0)^2 = 3 - 0 = 3.

Therefore, the point (0, 3) belongs to the graph of the function y = 3 - x^2.

2. To find the zero of the function y = -3x + 15, we need to find the value of x for which y equals zero. In other words, we need to solve the equation -3x + 15 = 0.

Subtracting 15 from both sides of the equation, we get:

-3x = -15.

Dividing both sides of the equation by -3, we find:

x = -15 / -3 = 5.

Therefore, the zero of the function y = -3x + 15 is x = 5.

I hope this helps! Let me know if you have any further questions.