Question

Найдите площадь и периметр прямоугольника, одна сторона которого 12 м, а другая в 4 раза меньше. (С краткой записью)

Answer 1

A=12;
b=12/4=3;
S=12*6=72м^2;
P=(12+3)*2=30м;
Ответ: S=72м^2; P=30m

Answer 2

Calculating the Area and Perimeter of a Rectangle

To find the area and perimeter of a rectangle with one side measuring 12 meters and the other side being 4 times smaller, we can use the following formulas:

Area of a Rectangle (A): A = length × width Perimeter of a Rectangle (P): P = 2 × (length + width)

Calculations

Given: - One side = 12 meters - The other side = 4 times smaller

Let's calculate the width of the rectangle: - If one side is 12 meters, the other side would be 12 ÷ 4 = 3 meters.

Now, we can calculate the area and perimeter using the formulas:

Area (A): A = 12 meters × 3 meters A = 36 square meters

Perimeter (P): P = 2 × (12 meters + 3 meters) P = 2 × 15 meters P = 30 meters

So, the area of the rectangle is 36 square meters and the perimeter is 30 meters.

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