Question

В двух кабинетах 68 стульев. когда из одного кабинета в другой перенесли 9 стульев то в 1 кабинете осталось на 3 ряда меньше чем во 2 . сколько стульев было в каждом кабинете первоначально?

Answer 1

3х+1х=68
4х=68
х=17 стульев было в первом кабинете после того как из него перенесли 9 стульев в другой кабинет.

17+9=26 стульев было первоначально в первом кабинете.
68-26=42 стульев было первоначально во втором кабинете.

Answer 2

Problem Analysis

We are given two rooms with a total of 68 chairs. When 9 chairs are moved from one room to the other, the first room ends up with 3 rows less than the second room. We need to determine the initial number of chairs in each room.

Solution

Let's assume the initial number of chairs in the first room is x and in the second room is y.

According to the given information, we have the following equations: 1. x + y = 68 (the total number of chairs in both rooms) 2. x = y - 3 (the first room has 3 rows less than the second room after moving 9 chairs)

To solve this system of equations, we can substitute the value of x from equation 2 into equation 1:

(y - 3) + y = 68 2y - 3 = 68 2y = 68 + 3 2y = 71 y = 71 / 2 y = 35.5

Since the number of chairs must be a whole number, we can conclude that the second room initially had 35 chairs.

Substituting this value back into equation 2, we can find the initial number of chairs in the first room:

x = 35 - 3 x = 32

Therefore, the initial number of chairs in each room was 32 and 35, respectively.

Answer

The initial number of chairs in the first room was 32, and in the second room was 35.