Question

Решите уравнения. Срочно. Пожалуйста то с объяснением. 1) (x+9)^2 - 36 = 0 2) x^4 - 5x^2 + 4 = 0 3) x^4 - 29x^2 + 100 = 0 4) 3y^4 + 2 + 7y^2 5)(z^2 - 5z)^2 - 12 = 4 (z^2 - 5z) - здесь решаеться через формулу сокращённого умножения. Спасибо.

Answer 1

Просто сделаем вид что тут более 20 символов

Answer 2

Уравнение 1: (x + 9)^2 - 36 = 0

To solve this equation, we can start by expanding the square term:

(x + 9)^2 = (x + 9)(x + 9) = x^2 + 18x + 81

Substituting this back into the equation, we have:

x^2 + 18x + 81 - 36 = 0

Combining like terms, we get:

x^2 + 18x + 45 = 0

Now, we can solve this quadratic equation by factoring or using the quadratic formula. Let's use the quadratic formula:

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation x^2 + 18x + 45 = 0, we have a = 1, b = 18, and c = 45. Substituting these values into the quadratic formula, we get:

x = (-18 ± √(18^2 - 4(1)(45))) / (2(1))

Simplifying further:

x = (-18 ± √(324 - 180)) / 2

x = (-18 ± √144) / 2

x = (-18 ± 12) / 2

This gives us two possible solutions:

x1 = (-18 + 12) / 2 = -6 / 2 = -3 x2 = (-18 - 12) / 2 = -30 / 2 = -15

Therefore, the solutions to the equation (x + 9)^2 - 36 = 0 are x = -3 and x = -15.

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