Вопрос задан 27.07.2018 в 20:03. Предмет Математика. Спрашивает Куярова Лера.

Запомнить таблицу Ширина Прямоугольник 17 м 36см. 18мм Пириметар 158см Площадь 624 дм в гводрате

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Отвечает Лис Макс.
Длина-158:2-36=43см
Площадь-36*43=1548 см2
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Table of Measurements:

To answer your question, I will provide a detailed breakdown of the given measurements and calculations.

- Width of Rectangle: 17 meters 36 centimeters - Width of Rectangle (converted to millimeters): 18 millimeters - Perimeter of Rectangle: 158 centimeters - Area of Rectangle: 624 square decimeters

Converting Measurements:

Let's start by converting the width of the rectangle from meters and centimeters to millimeters.

- Width of Rectangle: 17 meters 36 centimeters - Width of Rectangle (converted to millimeters): 17,360 millimeters

So, the width of the rectangle is 17,360 millimeters.

Calculating Perimeter:

Next, let's calculate the perimeter of the rectangle using the given measurements.

- Perimeter of Rectangle: 158 centimeters

The perimeter of a rectangle is calculated by adding the lengths of all its sides. Since the given measurement is in centimeters, we don't need to convert it.

To find the perimeter, we can use the formula: Perimeter = 2 * (Length + Width).

Since the width is not given, we can assume that the width is equal to the given width of the rectangle.

Let's denote the length of the rectangle as 'L' and the width as 'W'.

Using the formula, we can write the equation as: 158 = 2 * (L + 17,360).

Simplifying the equation, we get: L + 17,360 = 79.

Subtracting 17,360 from both sides, we find: L = -17,281.

However, a negative length is not possible in this context. Therefore, it seems there might be an error in the given measurements or calculations.

Calculating Area:

Lastly, let's calculate the area of the rectangle using the given measurements.

- Area of Rectangle: 624 square decimeters

The area of a rectangle is calculated by multiplying its length and width. Since the width is not given, we can assume that the width is equal to the given width of the rectangle.

Using the formula, we can write the equation as: Area = Length * Width.

Let's denote the length of the rectangle as 'L' and the width as 'W'.

Using the given area and the calculated width from the previous step, we can write the equation as: 624 = L * 17,360.

Simplifying the equation, we get: L = 0.0359.

However, a length of 0.0359 is not practical for a rectangle. Therefore, it seems there might be an error in the given measurements or calculations.

In conclusion, the given measurements and calculations for the width, perimeter, and area of the rectangle seem to have inconsistencies or errors. It would be helpful to double-check the measurements and calculations to ensure accuracy.

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